1. Calculation method of screen size
1. The calculation method of the indoor display.
(1) Give the specific data of the screen (length, width, area)
a. Example: The specification of the screen is Φ5 (refers to the diameter of the pixel) screen, the screen is 5.8 meters long and 2.6 meters wide.
b. First of all, clear the technical parameters of the Φ5 screen. The unit board specification is 488×244mm, and the unit board resolution is 64×32
c. Calculate the number of unit boards used.
Number of boards for screen length or width = pre-made screen length or width ÷ length or width of unit board
The number of boards used for screen length: 5.8 meters × 1000÷488=11.89≈1
The number of boards used for screen width: 2.6m×1000÷244=10.65≈
d. Calculate the actual screen siz
The actual screen length or width = the length or width of the unit board × the number of pieces used for the screen length or wid
Actual screen length: 488×12=5856mm or 5.856 mete
Actual screen width: 244×11=2684mm or 2.684 mete
e. Screen area: 5.856×2.684=15.72 (square meter
Note: Usually, the size of the outer frame of the screen is added 5-10cm to each side on the basis of the size of the scree
f. The resolution of the screen = the number of boards used for the screen × the resolution of the unit boa
Screen resolution = (12×64)×(11×3
(2) Only the area of the screen is given, without the length and widt
a. Example: Make a screen with an area of 9m2, and the size of the screen is Φ5 (referring to the diameter of the pixe
.
b. If only the area is given, we have to calculate the length and width by ourselves. It can be calculated according to the ratio of length and width 4:3 or 16:9. This picture effect is good. (Here take 4:3 as an examp
)
c. The theoretical screen length is: length = square root of (area ÷ 12) ?
4
Width = (area ÷ 12) square root × 3 That is: length = 3.46m width = 2.
m
d. The length and width have been calculated, see the example in (1) for the calculation bel
.
2. The calculation method of the outdoor displ
.
(1) Give the specific data (length, width, area) of the scre
.
a. Example: The outdoor full-color screen for P20 is about 10 meters long and 6 meters w
e
b. First of all, it is clear that the specification of the unit cabinet (cabinet length and width) is 1280×960mm, and the resolution is 64?
8
c. Calculate the number of box
.
Number of boxes for screen length or width = pre-made screen length or width ÷ length or width of unit
x
The number of cabinets used for screen length: 10m×1000÷1280=7.8123
?8
Number of cabinets for screen width: 6m×1000÷960=6.2
??6
d. Calculate the actual screen
ze.
The actual screen length or width = the (specification) length or width of the cabinet × the number of cabinets used for the screen length or
dth
Actual screen length: 1280×8=10240mm or 10.24 m
ers
Actual screen width: 960×6=5760mm or 5.76 m
ers
e. Screen area: 10.24×5.76=158.9824≈158.98 (square
ter)
f. Resolution of the screen = resolution length and width of the cabinet × length and width of the cabinet Each box = (64×8)×(
×6)
(2) Only the area of the screen is given, without the length and
dth.
a. Example: If you make a P20 outdoor full-color screen, the area is about 50 square m
ers.
b. If only the area is given, we have to calculate the length and width by ourselves. It can be calculated according to the ratio of length and width 4:3 or 16:9. This picture effect is good. (Here take 4:3 as an ex
ple)
c. The theoretical screen length is: length = square root of (area ÷ 12) × 4 width = square root of (area ÷ 12) × 3, namely: length = 8.16m width =
.12m
d. The approximate length and width have been calculated, and the following calculations refer to exampl
(1).
Second, the
brightness calculation method of the display
reen
Taking the full color screen as an example, usually the red, green, blue and white balance ratio is
:6:1
Brightness of red LED light: Brightness (CD)/M2÷points/M2×0.3 (30% of white balance rat
)÷2
Green LED light brightness: brightness (CD)/M2÷points/M2×0.6 (white balance ratio accounts fo
60%)
Brightness of blue LED light: brightness (CD)/M2÷points/M2×0.1 (white balance ratio accounts fo
10%)
(1) Know the brightness of the entire screen to find the brightness of a single
ube.
For example: 2500 dot density per square meter, 2R1G1B, the brightness requirement per square meter is 5000 cd/m2,
hen:
The brightness of the red
40mm Flexible LED Mesh Display light is: 5000÷2500×0.3÷2=0.3cd=
0mcd
The brightness of the green LED light is: 5000÷2500×0.6=1.2cd=1
0mcd
The brightness of the blue LED light is: 5000÷2500×0.1=0.2cd=
0mcd
The brightness of each pixel is: 0.3×2+1.2+0.2=2.0 cd=2
0mcd
(2) Find the brightness of the whole screen when the brightness of a single tube is
own.
For example: take P31.25, Nichia tube as an ex
ple.
Main die specifications of HSM display Red
reen
HSM-PH-A+ (Nichia) 180-440mcd 1020-24
mcd
Because the ratio of white balance to brightness is red: green: blue = 3:6:1; and the ratio of white balance is to match the brightness of green tube to other tubes. So as fo
ows:
From red: green = 3:6, we can see that the brightness of the green tube is twice that of the red tube, that is, the brightness of the red tube is: 2400 (blue) ÷ 2 = 1200mcd and because among the four tubes of red, green and blue, the red tube has 2 Therefore, the brightness of a single red tube is: 1200÷2=6
mcd.
From green: blue = 6: 1, it can be known that the brightness of the green tube is 6 times that of the blue tube, that is, the brightness of the blue tube is: 2400 (blue) ÷ 6 = 400mcd, because 1 luminous pixel = 2 red tubes + 1 green tube + 1 blue
ube;
That is, the brightness of a pixel=600(red)×2+2400(green)+400(blue)=3400mcd
.4cd
Brightness per square meter = brightness of 1 luminous pixel × pixel
density (number) per square meter = 3.4cd × 1024 (number of pixels) = 3482cd. Based on the calculation of light loss of 20%, the actual luminous brightness should be: 2785.28cd.